2p^2-7p-114=0

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Solution for 2p^2-7p-114=0 equation: 



2p^2-7p-114=0

a = 2; b = -7; c = -114;
Δ = b2-4ac
Δ = -72-4·2·(-114)
Δ = 961
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{961}=31$


$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-31}{2*2}=\frac{-24}{4}
=-6
$


$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+31}{2*2}=\frac{38}{4}
=9+1/2
$

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